0:00:15 | right |
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0:00:16 | i |
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0:00:18 | yeah |
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0:00:18 | rubber that there's particle filtering for |
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0:00:21 | we will have a description of a |
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0:00:23 | what the competition |
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0:00:25 | the main problem which is the |
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0:00:27 | a news |
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0:00:28 | a |
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0:00:28 | for |
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0:00:29 | part |
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0:00:30 | and then |
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0:00:31 | well let's part |
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0:00:32 | and is used to be for problem |
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0:00:35 | you have any fists right |
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0:00:36 | is how for white |
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0:00:38 | i at all |
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0:00:39 | at then |
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0:00:42 | em and or am decomposition is i up and they said a method for finalising on a station |
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0:00:48 | and nonlinear signals |
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0:00:50 | uh |
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0:00:51 | that can be a that can be used for analysing on a station and nonlinear a signals such as easy |
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0:00:56 | signal |
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0:00:56 | so he can be decomposed as a mixtures not to and number of was selected waveforms forms called intrinsic mode |
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0:01:03 | functions or i |
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0:01:05 | so if you have like emd to a mixture signal on we we can have a a number of i |
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0:01:09 | M F source of by the highest frequency to the low |
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0:01:12 | to the look that's frequency |
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0:01:14 | most times if if you first generated i S are noisy |
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0:01:17 | because they contain the highest frequencies in the mixture signal |
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0:01:22 | and because yeah an add up to |
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0:01:24 | is that is that they that that might what we can use the sum of generated i M S in |
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0:01:28 | order to construct the |
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0:01:30 | and them it's just not |
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0:01:35 | so yeah |
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0:01:36 | if we can see that the i M F as the real part |
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0:01:39 | it's you the transform at the complex part we can form an analytic signal using is on a takes signal |
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0:01:45 | we can estimate the instantaneous amplitude and is thing instantaneous frequent this phase of the |
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0:01:50 | i yeah |
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0:01:52 | and because the mixture signal can be reconstructed using the sum of i F these i S are the real |
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0:01:57 | part of these complex plot |
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0:02:00 | so have uh the main problem the |
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0:02:02 | uh the main problem is to estimate or tracked the east instantaneous phase |
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0:02:07 | of all sedation or or or of and i am |
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0:02:10 | so we can uh because the i'm if is noise scene if we consider these uh a question if the |
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0:02:15 | i'm if is noisy these instantaneous amplitude and these |
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0:02:18 | instantaneous phase is not the exact nine |
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0:02:22 | so the E the the object to used to estimate the actual east an instantaneous amplitude and he's then you |
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0:02:28 | a for me noisy i M it because if the i'm is a noisy these |
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0:02:32 | parameters on not the exact i |
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0:02:34 | here we try to use their of a lose the particle filtering you in order to |
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0:02:39 | uh track the instantaneous phase and amplitude of and i i i M |
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0:02:44 | uh the the idea is to extract these |
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0:02:46 | in some as amplitude and phase and formulated in the is that the space of the part get field day |
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0:02:51 | uh we we need to define the a state transition function and the observation function the vision function is simple |
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0:02:58 | because we can their the mixture signal the observation and those the vision function |
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0:03:02 | can be of using this formulation |
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0:03:05 | because this is the sum of i on the sum of i S can be a using these a question |
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0:03:09 | and |
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0:03:10 | these value of errors are for in the S it this space the main problem is to |
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0:03:14 | that term mean or are obtained the it's state transition function which is not |
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0:03:18 | and easy |
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0:03:19 | problem |
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0:03:20 | pro |
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0:03:22 | we can the like less part to get free in order to reform form that the problem them to use |
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0:03:27 | the size of the it's data space |
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0:03:29 | row but i colours particle filtering are extension of part to get thing that can be applied to |
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0:03:34 | conditionally linear |
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0:03:36 | a state value of a so if we partition a state is into linear part and nonlinear part we can |
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0:03:41 | estimate the |
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0:03:42 | you linear one using the con feeding and we can estimate the nonlinear for using particle filtering so you we |
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0:03:48 | like all but part to get free any |
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0:03:51 | we the rate use number of particles are required in order to estimate the |
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0:03:56 | a state of the system because the linear parties taken out an estimated by common fig |
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0:04:01 | so here we really is are proper them this is the observation and this is the observation function |
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0:04:08 | we can take the um to use instantaneous amplitudes uh uh out and form a big or |
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0:04:13 | this vector has a linear relation to to the mixture signal so these signal can be estimated by on free |
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0:04:19 | data |
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0:04:19 | and then this is the vector or of the them |
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0:04:22 | yeah of these there and the nonlinear linear S by are instantaneous phase |
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0:04:27 | so it is in san then it's phase are the non linear uh part of the problem so we need |
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0:04:32 | to use part to give any in order to estimate these value bits can i'm filter use used to estimate |
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0:04:37 | this of bits |
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0:04:38 | so the |
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0:04:40 | that's state this space size is a rate used to estimate this |
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0:04:44 | again the main problem used to define the state transition function |
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0:04:48 | so because um the main as state by a bizarre in then use phase |
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0:04:52 | we need to define a a a a state transition |
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0:04:56 | phase |
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0:04:57 | a a transition |
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0:04:58 | this is not that use the yeah this this can what |
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0:05:01 | we obtain easy because and the phase transition function |
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0:05:05 | it is a complex function in it cannot be you know model for example using a simple first-order order be |
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0:05:11 | an for example for |
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0:05:13 | instantaneous amplitude you |
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0:05:15 | we can use a first-order markov be amp says and then uh we can track the instantaneous amplitude but for |
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0:05:20 | instantaneous phase as you be seen lay later the slide |
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0:05:24 | the instantaneous phase actress different time points sees and |
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0:05:27 | for example is an increasing from minus pi to paul i and then this |
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0:05:31 | face face then change |
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0:05:33 | so these channel changing the face sign |
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0:05:36 | makes is |
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0:05:38 | phase transition function very complex we can not have a simple function in order to |
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0:05:43 | tear and the phase transition function |
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0:05:45 | so we formulate the problem of tracking instantaneous amplitude and phase using i M F and E M Ds |
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0:05:52 | we formulate a everything but that should used to determine the |
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0:05:56 | phase transition |
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0:05:57 | function which is a no |
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0:05:59 | it's very calm |
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0:06:00 | combine |
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0:06:03 | and |
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0:06:04 | we can uh |
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0:06:05 | if we have a |
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0:06:06 | access to that in to the estimated |
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0:06:09 | a face we and |
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0:06:10 | obtain the in the frequencies the frequencies can be of ten using the differentiation of the face so the instantaneous |
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0:06:17 | frequency can be obtained by differentiation of in as fate |
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0:06:22 | for a and scenes and i M if he's and all still a form in M narrowband frequency range |
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0:06:28 | the |
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0:06:29 | instantaneous frequency |
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0:06:31 | i close uh different time points are a small for example |
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0:06:35 | i because i i am of |
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0:06:36 | belongs to a a a a specific narrowband frequency range |
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0:06:40 | so we expect that the instantaneous frequency |
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0:06:43 | is a teen a a specific narrowband frequency range as that |
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0:06:47 | so we can use these information of the instantaneous frequency and try to include the information of instantaneous frequency in |
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0:06:55 | that the into the related particle filter |
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0:06:58 | so but using these team formation |
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0:07:01 | but using the information of the frequencies we can try to estimate the instantaneous fig |
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0:07:07 | so the objective is to |
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0:07:09 | uh track the instantaneous phase while at the same time try to a what the frequency traces |
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0:07:15 | because when and i am if is noisy and we estimate the instantaneous |
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0:07:18 | and the frequency we can see that the |
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0:07:21 | instantaneous frequency frequency's not to in a specific |
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0:07:24 | frequency band for example there is a sudden change in the in N as frequency at it goes on the |
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0:07:29 | frequency range |
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0:07:30 | so we can use this information these this assumption that for an oscillation or for and |
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0:07:35 | oh yeah may have the in and it's frequency should be a small |
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0:07:39 | median in a specific narrowband frequency range |
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0:07:42 | so we use the additional information of instantaneous frequency try to |
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0:07:47 | include these at the on information in to the out into their out formulated a but i as particle filtering |
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0:07:53 | and try to estimate the instantaneous phase |
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0:07:56 | in the |
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0:07:58 | now in in this work we first try to use only one on them if they or later can be |
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0:08:03 | extended for different number of uh a i for for example |
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0:08:07 | in face tracking of all of the i M F at the same time but uh for this work we |
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0:08:13 | one you see consider one T one i if the observation is only one i F which is a noisy |
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0:08:17 | this is the observation noise |
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0:08:19 | this is the observation function is simply |
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0:08:22 | and it can be a ten using these them considering the instantaneous amplitude and instantaneous phase using the hilbert transform |
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0:08:29 | and then this is the yeah a state transition function this very bizarre amplitude and phase of one i you |
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0:08:36 | may have one noisy i'm |
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0:08:38 | is in something as amplitude is estimated using con um filtering and this should be |
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0:08:42 | estimated using part if we can but as far as we don't have access to the |
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0:08:47 | instantaneous phase transition function we need to use the information of in and it's frequency in order to |
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0:08:54 | you how we can estimate the instantaneous |
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0:08:59 | this is there uh sort do code of the uh |
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0:09:02 | in some as face tracking uh the main objective is to |
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0:09:06 | first first in this for used to estimate the in and frequency the K S |
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0:09:10 | is to |
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0:09:11 | uh estimate the phase actress different time points but we also estimate the um |
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0:09:16 | but for amplitudes we only use |
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0:09:18 | first the markovian process in order to |
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0:09:21 | yeah in order to to find a a state transition what for phase as i said in the previous the |
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0:09:27 | slide is a complex function we cannot |
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0:09:29 | simply really use the more cold first order of you know for some but the face on a you change |
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0:09:35 | so there are some but part to get initialisation in this that's the |
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0:09:39 | and then uh |
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0:09:41 | a a for example when we want to estimate the it's state the phase |
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0:09:45 | is that it's phase at each time point |
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0:09:48 | we generate two faces |
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0:09:49 | one he's are ten by the positive of the phase in the previous time point plus a the of motion |
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0:09:55 | noise |
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0:09:56 | one is up from the negative |
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0:09:58 | of the phase in the previous part time point process a |
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0:10:02 | a coach and white noise |
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0:10:04 | so we generated two face in order to select between these two of phase |
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0:10:09 | we need to estimate the instantaneous frequency and try to see that each one of these phase |
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0:10:16 | tries to S smooth the instantaneous frequency meeting and narrowband frequency range |
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0:10:21 | so |
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0:10:22 | we also have one very but as the frequency |
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0:10:25 | and then we estimate this value but |
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0:10:28 | and we used use this a frequency by but comparing and and then we compare these uh a value but |
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0:10:33 | that's is a from the estimated frequency the previous time |
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0:10:36 | we compared to the frequency that it all that is a by each of considering in each of these phase |
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0:10:42 | and then we try to |
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0:10:43 | yeah i use these information of the frequency |
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0:10:47 | and then include it as the weight as some of uh as a B |
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0:10:51 | in order to all the weight of the particle filtering |
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0:10:54 | but the |
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0:10:55 | um when we try to use them |
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0:10:57 | but we implemented the at what that is |
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0:11:00 | this to look what was not uh working in and was not working in initial |
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0:11:05 | because |
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0:11:05 | there is the situation for example the phase transition is around zero |
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0:11:09 | but the face transition is around zero so then T |
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0:11:13 | and because we use the hilbert transform diff in some as frequency becomes negative it becomes part the positive and |
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0:11:19 | backs to the |
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0:11:20 | a a a a a specific frequency range that the i M F B don't |
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0:11:24 | so because is |
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0:11:25 | and |
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0:11:26 | uh these estimated frequency becomes negative is that because of the noise is because the phase transition is around zero |
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0:11:33 | is a special case |
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0:11:34 | in ours |
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0:11:35 | i'll go it we try to detect take this situation |
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0:11:38 | but the estimated instantaneous frequency is |
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0:11:41 | out of the frequency range but is not to to the noise or because of wrong estimation of the face |
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0:11:48 | from the positive or negative is because of phase transition around zero |
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0:11:51 | we detect take these situation so we use |
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0:11:54 | to to you as in order to update the weight of the particle |
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0:11:58 | and then at the if we have a uh some embedded part gets for example if the estimated phase is |
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0:12:02 | bigger than a i or less and minus by |
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0:12:05 | we set the weight of the invalid part can to zero in order not to have any contribution |
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0:12:10 | for the estimation of a state of the since |
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0:12:12 | or if they it it's an estimated in estimated as frequency |
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0:12:16 | is um |
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0:12:18 | large and then the maximum |
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0:12:19 | frequency of a a a specific |
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0:12:22 | but and that there are i M F don't |
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0:12:24 | we set the way to zero or if they estimate the once is a lower than the minimum frequency |
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0:12:30 | but the i mess and we as |
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0:12:31 | and we said the eight |
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0:12:33 | to weight of the part "'cause" to zero |
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0:12:35 | so we remove that you body part because |
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0:12:37 | so the important issue in in in this |
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0:12:40 | yeah in this to the so look what is that and because we can not seem really |
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0:12:45 | uh i have a |
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0:12:46 | function for phase transition we need to generate two phases one is from |
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0:12:51 | positive for face in then they get in the previous type point one is from negative of the in the |
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0:12:55 | previous i'm one |
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0:12:56 | then using the information of frequency |
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0:12:59 | we try to select between |
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0:13:01 | these two face also because |
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0:13:03 | we try to a mode the frequency traces actress different time points |
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0:13:08 | we we somehow hall |
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0:13:09 | a can the and really we somehow try to do noise the that it because for a noisy i'm F |
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0:13:14 | to estimated instantaneous frequency P on the frequency |
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0:13:18 | and also the for the is the a situation when the phase transition is a around zero we try to |
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0:13:24 | change are value |
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0:13:26 | we apply the at to set |
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0:13:28 | a two sets of simulated data or we generated for amplitude and frequency modulated sine wave we added a quotient |
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0:13:34 | wave not white noise |
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0:13:36 | the signals resolution is calculated using this formulation nation |
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0:13:40 | we can see that two snr levels tree and seven |
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0:13:44 | we estimate the instantaneous frequency using our proposed metal it also use the hilbert but transform of the noisy the |
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0:13:50 | i'm if and it is clear that in both the set of it are method |
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0:13:54 | uh oh or out forms the |
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0:13:56 | in then is frequent |
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0:13:57 | it the hilbert trance |
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0:13:59 | so this is one |
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0:14:01 | uh illustration for estimation of instantaneous phase |
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0:14:04 | the actual in something that's phase is that the act one |
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0:14:07 | and the for the noise is there red one the results of the tracking is a dot line |
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0:14:12 | so |
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0:14:13 | and you can see that uh for tracking we have a better estimation |
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0:14:16 | and you can see here for example the face signed so then change |
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0:14:19 | are i'll quickly takes these situation and here |
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0:14:22 | the phase transition is around zero |
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0:14:25 | so the estimated instantaneous frequency in these part should be negative but this is not to to the not because |
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0:14:30 | of these transition |
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0:14:31 | and then a are it can and attracting sent in both snr level is better than the you but |
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0:14:38 | this is the result of tracking instantaneous um P pretty to you |
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0:14:42 | and the this is in some then news freak estimate these i in set is frequency the phase transition around |
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0:14:47 | zero or this is the |
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0:14:49 | but i one is the actual one |
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0:14:50 | becomes negative but is is that because of noise because of the phase transition on zero |
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0:14:55 | it's still our method can it's what the frequency traces the noisy i am F |
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0:14:59 | is the rest one this and |
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0:15:01 | frequency |
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0:15:02 | so |
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0:15:04 | we try to keep the instantaneous frequency in and narrow frequency band range |
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0:15:10 | and then |
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0:15:10 | a we applied the all into the real eight are we can see there's a reach an and |
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0:15:15 | and then we estimate the incense and phase um pretty two |
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0:15:21 | and the this is the uh a smoothing results in frequency domain |
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0:15:26 | so the |
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0:15:27 | does line is the in sentence |
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0:15:29 | a a frequency tracking or is sporting using a rubber close but can fit the noisy i M F |
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0:15:34 | frequencies this |
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0:15:36 | so we propose a new face tracking system that uses both em the N L but i close but get |
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0:15:41 | printing the idea is to this what frequency traces |
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0:15:45 | and uh also use some if then has rules be at that some concern to the rubber like this party |
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0:15:50 | of fitting formulation |
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0:15:52 | we try to do you know is that i am if at the same time |
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0:15:55 | attracting tracking the nist face |
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0:15:57 | and uh a here later the problem and the method can be a you can be extended more in order |
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0:16:01 | to solve them all what makes mixing problem of the em this should be a exploited in another is there's |
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0:16:06 | and |
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0:16:07 | and the metal has application to and |
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0:16:10 | speech and has been also for |
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0:16:12 | phase a |
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0:16:13 | for |
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0:16:15 | basic synchronization of each just signal in different frequency band M on different region the method can be |
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0:16:49 | initial if we use only part to give we the number of |
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0:16:51 | a a a a a state |
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0:16:53 | a value as is high yeah but we partition the to very busy |
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0:16:56 | a linear non not being about |
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0:16:58 | uh so if we use a a use number of a state value as |
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0:17:03 | so that required number of part to get it should be low but |
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0:17:07 | but |
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0:17:07 | for one i am F because the S state only contains one phase |
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0:17:12 | so i i can see that at ten a on ten thousand part get |
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0:17:16 | yes because uh uh is because we use some a con constraint in that all but i close party think |
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0:17:21 | we need to |
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0:17:22 | have a number of a higher number of party in order to be like the the |
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0:17:25 | estimate the |
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0:17:26 | a a |
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0:17:27 | but if use several i am and |
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0:17:29 | so and and you have several and nonlinear possible of all phases |
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0:17:33 | we need to decrease the increase the number of a part |
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0:17:36 | it is a the some some minor problems with the part you're thinking is that |
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0:17:40 | a the number of for to gets |
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0:17:42 | in some cases should be high |
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0:17:44 | you know it have it like that |
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0:17:59 | propose a i used a pair you that's T |
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0:18:04 | so are used for a period then as the proposal density so |
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0:18:07 | uh the the rate can be up billy really using their weights |
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0:18:11 | in the previous time point multiplied by the likelihood function |
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